ImageVerifierCode 换一换
格式:PPT , 页数:55 ,大小:2.13MB ,
文档编号:4585417      下载积分:28 文币
快捷下载
登录下载
邮箱/手机:
温馨提示:
系统将以此处填写的邮箱或者手机号生成账号和密码,方便再次下载。 如填写123,账号和密码都是123。
支付方式: 支付宝    微信支付   
验证码:   换一换

优惠套餐
 

温馨提示:若手机下载失败,请复制以下地址【https://www.163wenku.com/d-4585417.html】到电脑浏览器->登陆(账号密码均为手机号或邮箱;不要扫码登陆)->重新下载(不再收费)。

已注册用户请登录:
账号:
密码:
验证码:   换一换
  忘记密码?
三方登录: 微信登录  
下载须知

1: 试题类文档的标题没说有答案,则无答案;主观题也可能无答案。PPT的音视频可能无法播放。 请谨慎下单,一旦售出,概不退换。
2: 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。
3: 本文为用户(晟晟文业)主动上传,所有收益归该用户。163文库仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对上载内容本身不做任何修改或编辑。 若此文所含内容侵犯了您的版权或隐私,请立即通知163文库(点击联系客服),我们立即给予删除!。
4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
5. 本站仅提供交流平台,并不能对任何下载内容负责。
6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。

版权提示 | 免责声明

1,本文(总体特征抽样调查的设计与分析课件.ppt)为本站会员(晟晟文业)主动上传,163文库仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对上载内容本身不做任何修改或编辑。
2,用户下载本文档,所消耗的文币(积分)将全额增加到上传者的账号。
3, 若此文所含内容侵犯了您的版权或隐私,请立即通知163文库(发送邮件至3464097650@qq.com或直接QQ联系客服),我们立即给予删除!

总体特征抽样调查的设计与分析课件.ppt

1、CHAPTER-6Sampling error and confidence intervalserrorSection 1 sampling error of meanSection 2 t distribution Section 3 confidence intervals for the population meanSection 1 sampling error of mean A simple random sample is a sample of size n drawn from a population of size N in such a way that every

2、 possible random samples n has the same probability of being selected.Variability among the simple random samples drawn from the same population is called sampling variability,and the probability distribution that characterizes some aspect of the sampling variability,usually the mean but not always,

3、is called a sampling distribution.These sampling distributions allow us to make objective statements about population parameters without measuring every object in the population.Example 1 The population mean of DBP in the Chinese adult men is 72mmHg with standard deviation 5mmHg.10 adult participant

4、s was chosen randomly from the Chinese adult men,here we can calculate the sample mean and sample standard deviation.Supposing sampling 100 times,whats the result?linkage5,72N11,SX22,SX33,SX001001,SX If random samples are repeatedly drawn from a population with a mean and standard deviation ,we can

5、find:1 the sample means are different from the others 2 The sample mean are not necessary equal to population mean 3 The distribution of sample mean is symmetric about HOW TO EXPLORE THE SAMPLING DISTRIBUTION FOR THE MEAN?The difference between sample statistics and population parameter or the diffe

6、rence among sample statistics are called sampling error.vIn real life we sample only once,but we realize that our sample comes from a theoretical sampling distribution of all possible samples of a particular size.The sampling distribution concept provides a link between sampling variability and prob

7、ability.Choosing a random sample is a chance operation and generating the sampling distribution consists of many repetitions of this chance operation.When sampling from a normally distributed population with mean,the distribution of the sample mean will be normal with mean Central limit TheoremXWhen

8、 sampling from a nonnormally distributed population with mean,the distribution of the sample mean will be approximately normal with mean as long as n is larger enough(n50).Central limit Theorem Standard error(SE)can be used to assess sampling error of mean.Although sampling error is inevitable,it ca

9、n be calculated accurately.Nxnssxtheoretical value of SEestimation of SECalculation of standard error(SE)sSEnSElinkagevExample 5.2 One analyst chose randomly a sample(n=100)and measured their weights with a mean of 72kg and standard deviation of 15kg.Question:what is the standard error?Solution:5.11

10、00/15/XnSS Exercise 5.1 Consider a sample of measurement 100 with mean 121cm and standard deviation 7cm drawn from a normal population.Try to compute its standard error.7.0100/7/SXnsSolution:Section 2 t distribution1.Definition /)(XZ N(,2)N(0,1)10 )()()(2211kksXsXsXRandom samplingXXZ/)(/)(XZXXSXXobv

11、iously,XSUsually standard deviation is unknown,so we can only get s,then we can calculate 1nondistributitsXx,This sampling distribution was developed by W.S Gossett and published under the pseudonym“student”in 1908.it is,therefore,sometimes called the“students t distribution and is really a family o

12、f distributions dependent on the n-1.XXZXsXt n-1Z distributiont distribution2.the characteristics of t distribution graphFIG 4 the graph of t distribution with different degrees of freedomv1 symmetric about 0;v2 the shape of t curve is determined by degree of freedom,df=n-1.v3 t-distribution is appr

13、oximated to standard normal distribution when n is infinite.t critical value with one-sided probability t(,)t critical value with two-sided probability t t(/2,)Example 5.2 With n=15,find t0 such that P(-t0t t0)=0.90solution From t value table,df=15-1=14,the two-tailed shaded area equals 0.10,so -t0=

14、-1.761 and t0=1.761 Section 3 confidence intervals for the population meanStatistical methodsIntervals estimationPoint estimation1.Basic concepts Parameter estimation:Deduce the population parameter basing on the sample statisticsPoint Estimate A single-valued estimate.A single element chosen from a

15、 sampling distribution.Conveys little information about the actual value of the population parameterabout the accuracy of the estimate.psXConfidence Interval or Interval Estimation An interval or range of values believed to include the unknown population parameter.Intervals estimation 2.MethodsZ dis

16、tribution1.is known2.is unknown,n50 t distribution is unknown,n5050XXZ),(nZxnZx2/2/CICIXsXt),(nStxnStx,2/,2/CICI Example 5.3 A horticultural scientist is developing a new variety of apple.One of the important traits,in addition to taste,color,and storability,is the uniformity of the fruit size.To es

17、timate the weight she samples 100 mature fruit and calculates a sample mean of 220g and standard deviation 5g Develop 95%confidence intervals for the population mean from her samplesolutionXXsZXsZX2/2/gLgL98.220100596.122002.219100596.122021 95%confidence intervals for the population mean is between

18、 219.02 and 220.98gExercise A forester is interested in estimating the average number of count trees per acre.A random sample of n=64 one acre is selected and examined.The average(mean)number of count trees per acre is found to be 27.3,with a standard deviation of 12.1.Use this information to constr

19、uct 95%confidence interval for.solution24.30641.1296.13.2736.24641.1296.13.2721LL 95%confidence intervals for the population mean is between 24.36 and 30.24XXsZXsZX2/2/The forester is 95%confident that the population mean for“count trees”per acre is between 24.36 and 30.24Example 5.4 The ecologist s

20、amples 25 plants and measures their heights.He finds that the sample has a mean of 15cm and a sample deviation of 4cm.what is the 95%confidence interval for the population mean solution)/()/(,2/,2/nstXnstXdf=25-1=24064.224,05.0tcmLcmL651.16254064.215349.13254064.21521 The plant ecologist is 95%confi

21、dent that the population mean for heights of these plants is between 13.349 and 16.651cmExercise 1 one doctor samples 25 men and measures their heights.He finds that the sample has a mean of 172.12cm and a sample deviation of 4.50cm.what is the 95%confidence interval for the population mean solution

22、cmLcmL98.173255.4064.212.17226.170255.4064.212.17221 95%confidence intervals for the population mean is between 170.26 and 173.98 Exercise 2 Random samples of size 9 are repeatedly drawn from a normal distribution with a mean of 65 and a standard deviation of 18.Describe the sampling distribution of mean.656.78918306.2654.61918306.26521LLPROBLEM1.What are the difference of SD and SE?2.What is the medical reference range?What is the confidence intervals for population mean?

侵权处理QQ:3464097650--上传资料QQ:3464097650

【声明】本站为“文档C2C交易模式”,即用户上传的文档直接卖给(下载)用户,本站只是网络空间服务平台,本站所有原创文档下载所得归上传人所有,如您发现上传作品侵犯了您的版权,请立刻联系我们并提供证据,我们将在3个工作日内予以改正。


163文库-Www.163Wenku.Com |网站地图|