1、 12;312 63183ba,cbcaba)0.(ccbcaba 类比分数的基本性质，你能想出分式有什么性质吗？怎样用式子表示分式的基本性质呢？)0.(CCC,CC解：解：m0 mambab22)0(22)1(mambmabambm2ana(2)bnb ab ananbnbn n0 2)(2,2 xxxxbaabba21)(）（)(222）（yxxxyx baaba222,)(baabba21)(）（aba 2baabba21)(）（)(222）（yxxxyx xaba 2baaba222,)(22bab 2)(2,2 xxxxxxxy xyxyxy xyyx22)1(c c1 15 5a
2、ab bb bc c2 25 5a a(2 2)2 23 32 23b3b5abc5abc5ac5ac5abc5abc2 2bac352 xxxy65)2(2)6(5.xxyx解：原式解：原式=65xy分析分析:提取公因式提取公因式x，再约分，再约分22m1(2)m2m1 2(m1)(m1)(m1)m1m1 cabbca2321525)1(969)2(22xxxbabcacabccabbca35551525)1(2232 bac352 222)3()3)(3(969)2(xxxxxx2)3()3)(3(xxx0.01x0.50.3x0.04 100)04.03.0(100)5.001.0(xx43050 xx32ab22ab3 6)32(6)232(babababa64912 2x3a 10m,5y7b3n2x 3a10m,5y 7b3n
