1、relationship, established equivalent relationship 14, and subject: application problem (4)-scores and percentage application problem review content overview answers scores, and percentage application problem of key is: according to meaning, (1) determine standard volume (units 1) (2) find associate
2、volume rate corresponds to relationship, Then in-line solution. Category fraction multiplication word problem score Division applications engineering problem problem XV, a subject: review of the measurement of the amount of capacity, measurement and units of measurement of common units of measuremen
3、t and their significance in rate 1, currency, length, area, volume, unit size, volume, weight and rate. (Omitted) 2, commonly used time units and their relationships. (Slightly) with a measurement units Zhijian of of poly 1, and of method 2, and poly method 3, and of method and poly method of relati
4、onship measurement distance of method 1, and tool measurement 2, and estimates 16, and subject: geometry preliminary knowledge (1)-line and angle review content line, and segment, and Ray, and vertical, and parallel, and angle angle of classification (slightly) 17, and subject: geometry preliminary
5、knowledge (2)-plane graphics review content triangle, and edges shaped, and round, and fan axisymmetric graphics perimeter and area combination graphics of area subject : Preliminary knowledge (3)-review of solid content category 1-d shapes are divided into: cylinder and cone 2, column is divided in
6、to: cuboid, square 3, cone cone of the features of cuboids and cubes relationship between characteristics of circular cone is slightly solid surface area and volume 1, size 2, table .和学乐教育数学解一元二次方程十字相乘法专项练习题(1) a27a+6=0； (2)8x2+6x35=0；(3)18x221x+5=0； (4) 209y20y2=0；(5)2x2+3x+1=0； (6)2y2+y6=0；(7)6x21
7、3x+6=0； (8)3a27a6=0；(9)6x211x+3=0； (10)4m2+8m+3=0；(11)10x221x+2=0； (12)8m222m+15=0；(13)4n2+4n15=0； (14)6a2+a35=0；(15)5x28x13=0； (16)4x2+15x+9=0；(17)15x2+x2=0； (18)6y2+19y+10=0；(19) 2(a+b) 2+(a+b)(ab)6(ab) 2=0； (20)7(x1) 2+4(x1)20=0参考答案：(1)(a-6)(a-1)，(2)(2x+5)(4x-7)(3)(3x-1)(6x-5)，(4)-(4y-5)(5y+4)(5)
8、(x+1)(2x+1)，(6)(y+2)(2y-3)(7)(2x-3)(3x-2)，(8)(a-3)(3a+2)(9)(2x-3)(3x-1)，(10)(2m+1)(2m+3)(11)(x-2)(10x-1)，(12)(2m-3)(4m-5)(13)(2n+5)(2n-3)，(14)(2a+5)(3a-7)(15)(x+1)(5x-13)，(16)(x+3)(4x+3)(17)(3x-1)(5x=2)，(18)(2y+5)(3y+2)(19)(3a-b)(5b-a)，(20)(x+1)(7x-17)解一元二次方程十字相乘法专项练习题 9.21一、 十字相乘分解因式：分解因式： 分解因式： 分解
9、因式： 二、用因式分解法解下列方程 (1) a27a+6=0； (2)8x2+6x35=0；(3)18x221x+5=0； (4) 209y20y2=0；(5)2x2+3x+1=0； (6)2y2+y6=0；(7)6x213x+6=0； (8)3a27a6=0；(9)6x211x+3=0； (10)4m2+8m+3=0；(11)10x221x+2=0； (12)8m222m+15=0；(13)4n2+4n15=0； (14)6a2+a35=0；(15)5x28x13=0； (16)4x2+15x+9=0；(17)15x2+x2=0； (18)6y2+19y+10=0；(19) 2(a+b) 2
10、+(a+b)(ab)6(ab) 2=0； (20)7(x1) 2+4(x1)20=0答案：十字相乘分解因式：分解因式： 分解因式： 分解因式： 参考答案：(1)(a-6)(a-1)，(2)(2x+5)(4x-7)(3)(3x-1)(6x-5)，(4)-(4y-5)(5y+4)(5)(x+1)(2x+1)，(6)(y+2)(2y-3)(7)(2x-3)(3x-2)，(8)(a-3)(3a+2)(9)(2x-3)(3x-1)，(10)(2m+1)(2m+3)(11)(x-2)(10x-1)，(12)(2m-3)(4m-5)(13)(2n+5)(2n-3)，(14)(2a+5)(3a-7)(15)(x+1)(5x-13)，(16)(x+3)(4x+3)(17)(3x-1)(5x=2)，(18)(2y+5)(3y+2)(19)(3a-b)(5b-a)，(20)(x+1)(7x-17)和平与发展是当今世界发展的主题，中国作为屹立在世界东方的大国，要担负起重要的责任。从“亚太自由贸易区”到“亚投行”、“一带一路”，再到G20峰会，都体现出中国一个负责任的大国形象。
