1、 CC 1()()dtu tiC从上面等式知：从上面等式知：(1)电容元件具有电容元件具有通交流隔直流通交流隔直流的作用。的作用。(2)通过电容的电流通过电容的电流ic为有限值，电容两端的电压是时为有限值，电容两端的电压是时间间t的的连续函数连续函数，不能突变。，不能突变。(3)电容器两端的电压电容器两端的电压uc(t)与与t时刻以前的电流有关，即时刻以前的电流有关，即电容器具有电容器具有“记忆记忆”电流的功能电流的功能。CCdddduqiCttCC1d()()duti ttC C()u 2C1()()2w tCutCCCCd()()()()()dutp tut i tCutt CC 22CC
2、()()d ()d()11 ()()22ttw tpCuuCutCu610 2sin(90)10 23144.75 10sin(31490)0.015 2sin(31490)ACttt10 2sin()t2C1()()2w tCutCCdddduqiCttCC()()()p tut i t10 2sin(314)0.015 2cos(314)0.15sin(628)Wttt62o14.75 1010 2sin(314)20.000240.00024sin(62890)JttL()()tLi tLd()duttLLd()diutLt LLL()()()d ()dLp tut i tiLi tt
3、L()()dtw tpLL()LL()()d()itiLii2L1()2Lit2C12Cu2L12Li CCLL00(0)(0)uuii（）（）C(0)(0)uL和iC1+C1-C2+C2-S2L+L-S u(0)=u(0)=0 u(0)=u(0)=I R i(0)=i(0 )=ILSSSSS21S1S22S1(0)000uI RI RI RiIRI RiIR12C(0)(0)(0)iii、和CC(0)0,(0)12ViuCC(0)(0)12VuuSC11(0)(0)0UuiRC22(0)(0)1.5AuiRC12(0)(0)(0)1.5Aiii 。t（）1()0t00tt 1CS()etRC
4、u tUt（）1CSd()edtRCu tUi tCttR）（）C1(0)(0)2CwCu3C63623CC32022 10(0)20V10 105 1010 105 10s(020(0)4 10A5 10CwuCRCuiR（）50C()20etu t350C(t)4 10 eti 5020e8t1C()20etRCu tC20lnuttC（）1CS()(1e)tRCutUt（）1S()etRCUi ttR（）CCSCS(0)(0)0(0)()()uuUiRRi tutU365 101000 105sRC 1CS()(1e)tRCu tUt（）S120.0024A5UR15()12(1e)tC
5、utt（）V1S()etRCUi ttR（）15()0.0024eti tt（）A2212CUCC1d()()dutRCutUt11C21()e1 ettRCRCu tUU（）1C211()()etRCutUUUCC2225(0)00.5wuuC-（）=10 v 2CS123939RuURR（+）=2.25v=RC=(R1/R2)C=1.125s 111.1251.125C()(102.25)e2.25(2.25 7.75e)ttut=+V1C1.1252()()0.752.58etuti tRA 2C1()2wCut1()Uf2(0)Uf1()()(0)()etf tfff(0)f()f(0
6、)f()f 2CS1232()12 4V222RuURRR=614 10C=4(1-e)Vtueq132eq4()/K34 sRRRRR CS12URRR2L0uuLL02dedtiuLI Rt 1L0etiI2RL02etuuI R 0200(0)5A40SUIiR1L0etiI11000.01L5e5etti100100LLd0.5 5(100)e250eVdttiuLt 100100L=i=5e40200eVttRuR00.01sLRR 1L2L1212L12L121212UuUuUURRiiiuRRRRR RL1212L1212d1()diR RUUitL RRRR LLdLdiut1
7、2eq12R RRRR12eq121s2RRLLRR R/12L12etUUiCRRLL11(0)(0)/iiUR22/CUR 22L23(1e)(53e)tti/12L12(1e)tUUiRRLL(0)(0)0ii=SL()UiR SLLddUiRitLL SLLLSRLS()(1e)d()ed()(1e)tttUi tRiutLUtuti RULRLL(0)()ii、S101A10UIR0.5sLR2LS()e10e10VttutULS()e0VtutU SSL0()e(1e)ttUUi tRRRSSSS0()tLUUUUieRRRRRSL0100(0+)1A5050UiRRSL()UiR S1002A50UR15010s5RL1010L(t)=2+(1-2)e=(2-e)Atti1010LLd()5 10e50eVdttiutLtSLL0(0)(0)UiiRR WTwT2ToUetu2Tw()/o()et Tu tU CiodddduuuRCRCttWTwTwT2To()(1e)tu tU21o(/2)(1e)TUu TU2T()2o1()eTtu tUoCi11dduui tu tCRCwT
