1、Power ElectronicsLecture (7)Prof. Mohammed Zeki KhedherDepartment of Electrical EngineeringUniversity of Jordan1Single-Phase Full-Wave Diode Rectifier Center-Tap Diode Rectifier mmdcVtdtVV2sin10RVImdc22sin102mmrmsVtdtVVRVImrms2PIV of each diode = mV2RVIImDS2Example 3. The rectifier in Fig.2.8 has a
2、purely resistive load of R Determine (a) The efficiency, (b) Form factor (c) Ripple factor (d) TUF (e) Peak inverse voltage (PIV) of diode D1 and(f) Crest factor of transformer secondary current.%05.812*22*2*RVVRVVIVIVPPmmmmrmsrmsdcdcacdc11. 12222mmdcrmsVVVVFF483. 0111. 1122FFVVRFdcacThe PIV is mV2S
3、ingle-Phase Full Bridge Diode Rectifier With Resistive Load Example 4 single-phase diode bridge rectfier has a purely resistive load of R=15 ohms and, VS=300 sin 314 t and unity transformer ratio. Determine (a) The efficiency, (b) Form factor, (c) Ripple factor, (d) The peak inverse voltage, (PIV) o
4、f each diode, , and, (e) Input power factor.VVtdtVVmmdc956.1902sin10ARVImdc7324.122VVtdtVVmmrms132.2122sin12/102%06.81rmsrmsdcdcacdcIVIVPP11. 1dcrmsVVFF482. 01122222FFVVVVVVVRFdcrmsdcdcrmsdcacThe PIV=300V Input power factor = 1cosReSSSSIVIVPowerApperantPoweralComparision between Single Phase Rectifi
5、ers Half wave Full wave Fullwave center-tap bridgePeak repetitive reverse voltage VRRM 3.14Vdc 3.14 Vdc 1.57 VdcRms input voltage per transformer leg Vs 2.22 Vdc 1.11 Vdc 1.11 VdcDiode average current IF.AV. 1.00 Idc 0.50 Idc 0.50 IdcDiode rms current IF.RMS. 1.57 Idc 0.785 Idc 0.785 IdcForm factor
6、of diode current IF.RMS. 1.57 1.57 1.57Rectification ratio 0.405 0.81 0.81Form factor 1.57 1.11 1.11Ripple factor 1.21 0.482 0.482Transformer rating primary VA 2.69 Pdc 1.23 Pdc 1.23 PdcTransformer rating secondary VA 3.49 Pdc 1.75 Pdc 1.23 PdcOutput ripple frequency fr 1 fi 2 fi 2 fiMulti-phase Rec
7、tifierThree-Phase Half Wave Rectifier mmmdcVVtdtVV827. 0233sin236/56/RVRVImmdc*827. 0*233mmmrmsVVtdtVV8407. 083*321sin236/56/2RVImrms8407. 0RVRVIImmSr4854. 0308407ThePIV of the diodes is mLLVV32Example A 3-phase star rectifier is operated from 460 V 50 Hz supply at secondary side and the load resist
8、ance is R=20. If the source inductance is negligible, determine (a) Rectification efficiency, (b) Form factor (c) Ripple factor (d) Peak inverse voltage (PIV) of each diode.VVVVmS59.3752*58.265,58.2653460mmdcVVV827. 0233RVRVImmdc0827233mrmsVV8407. 0RVImrms8407. 0%767.96rmsrmsdcdcacdcIVIVPP%657.101dc
9、rmsVVFF%28.181122222FFVVVVVVVRFdcrmsdcdcrmsdcacThe PIV=3Vm=650.54V Three-Phase Full Wave Rectifier With Resistive Load 135462bcILVLIsIpaExample 10 The 3-phase bridge rectifier is operated from 460 V 50 Hz supply and the load resistance is R=20ohms. If the source inductance is negligible, determine (
10、a) The efficiency, (b) Form factor (c) Ripple factor (d) Peak inverse voltage (PIV) of each diode .VVVVmmdc226.621654. 133ARVRVImmdc0613.31654. 133VVVVmmrms752.6216554. 143*923ARVImrms0876.316554. 1%83.99rmsrmsdcdcacdcIVIVPP%08.100dcrmsVVFF%41122222FFVVVVVVVRFdcrmsdcdcrmsdcacThe PIV=3Vm=650.54V Single phase rectifier 3 phase rectifierPerformance:3-phase bridge rectifier with RL loadCondition for continuous load current 谢谢你的阅读v知识就是财富v丰富你的人生docin/sanshengshiyuandoc88/sanshenglu 更多精品资源请访问更多精品资源请访问
