1、通过交换获得提供),/()1(niPFPiPFn),/()1(niPFPiPFn),/()1(niFPFiFPn),/()1(niPFPiPFn0123n-1nPF01 23n-1nF0123n-1nPAAAAA),/(1)1(niAFAiiAFn),/(1)1(niFAFiiFAn),/()1(1)1(niAPAiiiAPnn),/(1)1()1(niPAPiiiPAnn),/(niPF),/(niPF),/(niFP),/(niFP),/(niAF),/(niFA),/(niAP),/(niPAiniFAniPA),/(),/(1)1()1(1)1()1(),/(nnnniiiiiiiin
2、iPAiniFAiiin),/(1)1()1()1(1ntGtAAt123n-1n0A1P=?+图A图B图CA1+(n1)G GAPPP),/(1niAPAPAnGiniiGP)1(1)1(2)1(132)1(i12)1(1)1(2)1(1)1(nGiniiGiPnnnnnnnnGinGiiiGinGiiiiGiniiiGiP)1()1(1)1()1()1(1)1(1)1(1)1(1 )1(1)1(1)1(1)1(11212),/()1()1(1)1(1niGPGiniiiiGPnnnG),/(),/(1niGPGniAPAP定差现值系数nniniGiiGiAP)1()1(1121 21iGi
3、APnniniGiiGiAP)1()1(1121 21iGiAPniPF)1(GG),/(1)1(2niGFGiniiGFnG定差终值系数),/(),/(1niGFGniAFAF定差年金系数GAAA11)1()1()1()1(1)1(),/(nnnnnGGiiiiniiiiGniPAPA1)1(1niniG),/(niGAG),/(1niGAGAA),/(1njiAPAP),/(1njiAFAF等比数列现值系数等比数列终值系数ji nijjiAP1111ji niAP11jijiAP1nijjiAP1111jiAP1mmrPF)1(1)1(mmrPPFI1)1(mmrPIi11111)1(li
4、mlimrrrmrmmmmemri连45.62897%)101()8%,10,/(5000AFF39.51745%)81()5%,8,/(12000APP39.51745)4%,8,/(1200012000APP39.51745)4%,8,/()5%,8,/(12000FPAFP7.5)3%,10,/()5%,10,/(2FPAPP【例例4】：若利率为6%，现存入多少可使今后30年每6年末提取2000元？解：P2000（A/F，6%，6）（P/A，6%，30）3947.7iAiiiAPnnn)1(1)1(lim 该例题的现值为 6500%101505000P%266.6397.2172.3397.25.2%2%6%6%8397.2172.3%6397.25.2ii解法2：%27.615.215i
