《高数双语》课件section 2-2.pptx

上传人(卖家):momomo 文档编号:5897854 上传时间:2023-05-14 格式:PPTX 页数:23 大小:607.02KB
下载 相关 举报
《高数双语》课件section 2-2.pptx_第1页
第1页 / 共23页
《高数双语》课件section 2-2.pptx_第2页
第2页 / 共23页
《高数双语》课件section 2-2.pptx_第3页
第3页 / 共23页
《高数双语》课件section 2-2.pptx_第4页
第4页 / 共23页
《高数双语》课件section 2-2.pptx_第5页
第5页 / 共23页
点击查看更多>>
资源描述

1、Rules for Finding DerivativesDerivation rules for sum,difference,product and quotient of functions2(Derivation rules of rational operations)Suppose that the function f,:Rg I xI are derivable at;then their sum,difference,product and quotientare all derivable at x,and()()()()fgxfxg x(1)()()()()()()fgx

2、fx g xf x g x(2)2()()()()()()0)()ffx g xf x g xxg xggx (3)In particular()()()cfxcfx Rc (is a constant),21()()()0)()fxxf xffx .Derivation rules for sum,difference,product and quotient of functions3Lets prove only the rule(2).()()()()yf xx g xxf x g x By the definition of the derivative,we have()()yf

3、x g x Let ,then Proof:()()()()()()()()f xx g xxf x g xxf x g xxf x g x 0()()limxyfgxx Since is derivable at ,()g xxit must be continuous at x and henceThereforeFinish.()()()()()()fgxfx g xf x g x.0lim()()xg xxg x .00lim()lim()xxfgg xxf xxx .()()g xxff xg .Derivation rules for sum,difference,product

4、and quotient of functions4Find the derivative of223cosln.xyxxxxSolution:By rules(1)and(2),we have Finish.2()(2)(3cos)(ln)xdyxxxxdx22 ln23sin()ln(ln)xxxxxxxln22 ln23sin2xxxxxxxln122 ln23sin2xxxxxx.Derivation rules for sum,difference,product and quotient of functions2(tan)secxx 2(cot)cscxx 5tanyx coty

5、x Find the derivative of and .Solution:By the quotient rule,we have2(sin)cos(cos)sincosxxxxx 2(tan)secxx 2(cot)cscxx That is By the same way,we haveFinish.2222cossinseccosxxxx sin(tan)cosxxx Derivation rules for sum,difference,product and quotient of functions62xyx Find the equation for the tangent

6、to the curve at the point(1,3).Solution The slope of the curve is 222()1.yxxx Then the slope at x=1 is 1()1.xy The line through(1,3)with slope m=-1 is 3(1)yx Finish.or4.yxDerivation rules for sum,difference,product and quotient of functions00lim()lim()(0).xxf xf xf7Solution:Determine the constants a

7、 and b,such that the functionis continuous and derivable on 223,0,(),0,xxxf xaxbx (,).Notice that f(x)is a polynomial function while x 0 or x 0.1(ln|)(ln);xxxWhen x 0,then prove that ()()()()()ln()v xv xu xu xv xu x .Examples192(ln(12)dyxxxdx,dydxExample 1:Findwhere2ln(12).yxxxSolution:221(12)12xxxx

8、xx22122(1)122 2xxxxxx21.2xxFinish.Examples20()()ln()(),v xv xu xu xe()()ln()()v xv xu xu xe ()()()ln()v xu xv xu x ()ln()()ln()v xu xev xu x ()u x()v xExample 2:If and are both derivable on I,and u(x)0,then prove that()()()()()ln()v xv xu xu xv xu x .Proof:Since we have Finish.Examples21 ()()()()()l

9、n()v xv xu xu xv xu x lnxxxxxx 1(ln)xxxxx,dydx(0).xyxxExample 3:FindwhereSolution:(ln1).xxxFinish.xxx Could you find?Examples222.yaxbxcExample 4:If axis x is the tangent line of a parabola,What conditions will a,b and c satisfy?02bxa 20.22bbabcaaSolution:()yf x Since axis x is the tangent line of ,t

10、hen the tangent point0(,0)xwill have the formand it is satisfying thatandTherefore00 x xdyydx (2)020axb(3)By(3),we have0 xand substitute in(1),we have2000axbxc(1)Finish.23(1)()0c (where c is a constant)(2)()lnxxaaa (0a ,1a )(3)()xxee (4)1()()xxR (5)(sin)cosxx (6)(cos)sinxx (7)2(tan)secxx (8)2(cot)cscxx (9)(sec)sectanxxx (10)(csc)csc cotxxx (11)1(ln)xx (12)1(log)(0,1)lnaxaaxa (13)21(arcsin)1xx (14)21(arccos)1xx (15)21(arctan)1xx (16)21(arccot)1xx (17)(sinh)coshxx (18)21(arcsin)1hxx (19)(cosh)sinhxx (20)21(arccos)1hxx (21)2(tanh)1/coshxx (22)21(arctan)1hxx

展开阅读全文
相关资源
猜你喜欢
相关搜索
资源标签

当前位置:首页 > 大学
版权提示 | 免责声明

1,本文(《高数双语》课件section 2-2.pptx)为本站会员(momomo)主动上传,163文库仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对上载内容本身不做任何修改或编辑。
2,用户下载本文档,所消耗的文币(积分)将全额增加到上传者的账号。
3, 若此文所含内容侵犯了您的版权或隐私,请立即通知163文库(发送邮件至3464097650@qq.com或直接QQ联系客服),我们立即给予删除!


侵权处理QQ:3464097650--上传资料QQ:3464097650

【声明】本站为“文档C2C交易模式”,即用户上传的文档直接卖给(下载)用户,本站只是网络空间服务平台,本站所有原创文档下载所得归上传人所有,如您发现上传作品侵犯了您的版权,请立刻联系我们并提供证据,我们将在3个工作日内予以改正。


163文库-Www.163Wenku.Com |网站地图|