（2019）新人教版高中化学选择性必修一第四章第1节原电池第2课时 化学电源 进阶检测（原卷+解析版）.rar

第二章第 1 节 原电池第 2 课时 化学电源【随堂检测】1. .“”(1).电.电.(.)(2).电电.电.(.)(3).电. Li .电.(.)(4).电.电时.电源.(.)(5).电.电时.Li.(.)(6).电.电.电.电.电.(.)(7).“.”.“.”.电.电.(.)(8).电.电.源.(.)(9).电.化.电.(.)(10).电.(.)(11).电.(.电.). O2.电. O2.4H.4e.=2H2O(.)(12).电.电.化学.(.)(13).电.电.H.(.)2.电.Zn.2NH=Zn2.2NH3.H2.(.) 4A.电.B.电.时 NH.化 4C.电.化学.化进阶检测step by stepD.电. Zn 电.电.电.3.电.电.(.). NH4Cl . ZnCl2.电.(.MnO2. H2).电.化. Zn.2e.=Zn2.2NH.2e.=2NH3.H2NH3. Zn2. 4Zn(NH3)42.(.)A.Zn .B.Zn .C.时电.电. Zn .D.时.时.电.4. N2. H2. A .电.电.(.)A.b 电.化.B.a 电. N2.8H.6e.=2NH 4C.A . NH4ClD. 1 mol N2时. H2. 67.2 L5.电.电电.电. Pb.PbO2.4H.2SO=2PbSO4.2H2O.24.电时.电._.电. H2SO4._.电.1 mol 电.时._ g.电._.【基础再现】1.电.电.电源.电.电. Ag2O . Zn.电. KOH . Ag2O.H2O.Zn=Zn(OH)2.2Ag.(.)A.Ag2O .Zn .B.Zn .Ag2O .C.时.电. pH .D.时.电. Ag2O .电. Zn .2.电. Pb.PbO2.电. H2SO4.时.电.Pb.PbO2.2H2SO4=2PbSO4.2H2O.(.)A.Pb .化B. pH .C.SO. PbO2.24D.电.3.电.(.)A.电.化.B.电.C.电.电.D.电. O2.4H.4e.=2H2O4.化.化.(CH3CHO).电.(.)A. 0.1 mol O2. H. 0.4 molB. CH2=CH2.2e.2OH.=CH3CHO.H2OC.电.电. a.电. b.电.电. aD.电.电电.5.电.电电.电.电.时.电电.电. 3Zn.2K2FeO4.8H2O=3Zn(OH)2.2Fe(OH)3.4KOH.(1).电._.电时._.(2).电时._(.“.化”.“.”)._.电时._(.“.”.“.”).【能力提升】1.电.电电.电.化.电.电. Zn(s).2MnO2(s).2H2O(l)=Zn(OH)2(s).2MnO(OH)(s).(.)A.电.时.电.B.电.电. 2MnO2(s).2H2O(l).2e.=2MnO(OH)(s).2OH.(aq)C.电.时.电.电.D.电. 0.2 mol 电. 6.5 g2.学.电.电源.(.)A.电.时.电.电.电.B.化.电.C.电. 2Li.2H2O=2LiOH.H2.D.电.3.电.电.(.)A. CH4.H2O3H2.CO. 1 mol CH4. 12 mol 电.= = = = =催化剂 .B.电. A . H2.电. H2.2OH.2e.=2H2OC.电.时.CO.电. B .23D.电. B .电. O2.2CO2.4e.=2CO234.“.电.”NOx.化.化.(.)A. “.电.”.B. “.电.”.电. NO2.2H.2e.=NO.H2OC.时.H.“.电.”.“.电.”D. “.电.”.5.(2020.源.).电.电.电.电.电.电.电.化.学.电.电. Cu.PbO2.2H2SO4=CuSO4.PbSO4.2H2O.(.)A.a .b .B.电.时 PbO2电. pH .C.a .电. Cu.2e.=Cu2.D.电. CuSO46.(1)SO2.CO.CO2.NOx.化.电化学. CO.SO2.化.化. . A . CO.B . H2.C . CH3OH. CO .电._.A . SO2.B . O2.C . H2SO4._. A . NO2.B . O2.C . HNO3.电._.(2).电._._.电._.电.时. 5.4 g ._mol.(3). Cu.Fe2(SO4)3=2FeSO4.CuSO4.电._.电.电._.第二章第 1 节 原电池第 2 课时 化学电源【随堂检测】1.( (“”(1)(电(电()(2)(电电(电()(3)(电( Li (电()(4)(电(电时(电源()(5)(电(电时(Li()(6)(电(电(电(电(电()(7)(“(”(“(”(电(电()(8)(电(电(源()(9)(电(化(电()(10)(电()(11)(电(电()( O2(电( O2(4H(4e(=2H2O()(12)(电(电(化学()(13)(电(电(H()答案(1)(2)(3)(4)( (9)(10)(2(13)2.(电(Zn(2NH=Zn2(2NH3(H2() 4A(电(进阶检测step by stepB(电(时 NH(化 4C(电(化学(化D(电( Zn 电(电(电(答案D解析(电(Zn (电( A (电时(NH(电( 4( B (电(化学(化(电( C (电时(电( Zn ( D (3(电(电()( NH4Cl ( ZnCl2(电(MnO2( H2)(电(化( Zn(2e(=Zn2(2NH(2e(=2NH3(H2NH3( Zn2( 4Zn(NH3)42()A(Zn (B(Zn (C(时电(电( Zn (D(时(时(电(答案(A解析(电(Zn (化(电(电(电(电(电(电(时(时(MnO2( H2(电(电(4( N2( H2( A (电(电()A(b 电(化(B(a 电( N2(8H(6e(=2NH 4C(A ( NH4ClD( 1 mol N2时( H2( 67.2 L答案(D解析N2(3H2(2NH3(化(H2(电( b 电(化( A (a 电(电(电( N2(8H(6e(=2NH( B ( B (A ( NH4Cl( C ( 4( D (5(电(电电(电( Pb(PbO2(4H(2SO=2PbSO4(2H2O(24(电时(电(_(电( H2SO4(_(电(1 mol 电(时(_ g(电(_(答案PbO2(2e(4H(2SO=PbSO4(2H2O(48(1 mol24解析(1)电(Pb(PbO2(4H(2SO=2PbSO4(2H2O(24Pb(2e(SO=PbSO4(PbO2(2e(4H(2SO=PbSO4(2H2O(电( H2SO4(2424(电( 1 mol 电(时(电( 0.5 mol303 gmol(1(0.5 mol207 gmol(1(48 g(【基础再现】1(电(电(电源(电(电( Ag2O ( Zn(电( KOH ( Ag2O(H2O(Zn=Zn(OH)2(2Ag()A(Ag2O (Zn (B(Zn (Ag2O (C(时(电( pH (D(时(电( Ag2O (电( Zn (答案(A解析(电(化(电(化(电(电(A (B ( pH (C (电(时(电(电(化(D (2(电( Pb(PbO2(电( H2SO4(时(电(Pb(PbO2(2H2SO4=2PbSO4(2H2O()A(Pb (化B( pH (C(SO( PbO2(24D(电(答案D解析(电(化(电(时(电(电(电(SO( OH()( pH (24(3(电()A(电(化(B(电(C(电(电(D(电( O2(4H(4e(=2H2O答案(D解析(电(电( A (电(电(化( B ( C (电( O2(4H(4e(=2H2O( D (4(化(化(CH3CHO)(电()A( 0.1 mol O2( H( 0.4 molB( CH2=CH2(2e(2OH(=CH3CHO(H2OC(电(电( a(电( b(电(电( aD(电(电电(答案(A解析( O2(4H(4e(=2H2O ( 0.1 mol O2( H(0.4 mol(A (电(电( O2(4H(4e(=2H2O(B (电时电(电( a (电( b(C (电时(电(电电(D (5.(电(电电(电(电(时(电电(电( 3Zn(2K2FeO4(8H2O=3Zn(OH)2(2Fe(OH)3(4KOH(1)(电(_(电时(_(2)(电时(_(“(化”(“(”)(_(电时(_(“(”(“(”)(答案(1)Zn(3Zn(6OH(6e(=3Zn(OH)2(2)(2FeO(6e(8H2O=2Fe(OH)3(10OH(24解析(电时(电(化( 3Zn(6OH(6e(=3Zn(OH)2( 2FeO(6e(8H2O=2Fe(OH)3(10OH( OH(24(【能力提升】1(电(电电(电(化(电(电( Zn(s)(2MnO2(s)(2H2O(l)=Zn(OH)2(s)(2MnO(OH)(s)()A(电(时(电(B(电(电( 2MnO2(s)(2H2O(l)(2e(=2MnO(OH)(s)(2OH(aq)C(电(时(电(电(D(电( 0.2 mol 电( 6.5 g答案(C解析(电(电(电(电( 0.2 mol 电( 0.1 mol( 6.5 g(2(学(电(电源()A(电(时(电(电(电(B(化(电(C(电( 2Li(2H2O=2LiOH(H2(D(电(答案(B解析A (电(电(电(B (电(C (电( 2Li(2H2O=2LiOH(H2(D (电(电(3(电(电()A( CH4(H2O3H2(CO( 1 mol CH4( 12 mol 电(= = = = =催化剂 (B(电( A ( H2(电( H2(2OH(2e(=2H2OC(电(时(CO(电( B (23D(电( B (电( O2(2CO2(4e(=2CO23答案D解析A (H4(O( 1 mol CH4( 6 mol 电(B (电(C4 C2 (电( A ( H2(电( H2(2e(CO=CO2(H2O(C (23(电(时(电( B (D (电( B ( O2(电(O2(4e(2CO2=2CO(234(“(电(”NOx(化(化()A( “(电(”(B( “(电(”(电( NO2(2H(2e(=NO(H2OC(时(H(“(电(”(“(电(”D( “(电(”(答案(D解析(电( NO2( NO(化(电(电( A (“(电(”(电( NO2(2H(2e(=NO(H2O( B (时(H(“(电(”(“(电(” ( C (电( “(电(”( D (5(2020(源()(电(电(电(电(电(电(电(化(学(电(电( Cu(PbO2(2H2SO4=CuSO4(PbSO4(2H2O()A(a (b (B(电(时 PbO2电( pH (C(a (电( Cu(2e(=Cu2(D(电( CuSO4答案(D解析电( Cu(PbO2(2H2SO4=CuSO4(PbSO4(2H2O(电(化(PbO2(电( a (b ( A (PbO2(电(电( PbO2(4H(SO(2e(=PbSO4(2H2O( PbO2电( pH ( B (24(电(化(电(Cu(2e(=Cu2( C (电(Cu(PbO2(2H2SO4=CuSO4(PbSO4(2H2O (电( H2SO4( D (6(1)SO2(CO(CO2(NOx(化(电化学( CO(SO2(化(化( ( A ( CO(B ( H2(C ( CH3OH( CO (电(_(A ( SO2(B ( O2(C ( H2SO4(_( A ( NO2(B ( O2(C ( HNO3(电(_(2)(电(_(_(电(_(电(时( 5.4 g (_mol(3)( Cu(Fe2(SO4)3=2FeSO4(CuSO4(电(_(电(电(_(答案(1)(CO(4e(4H(=CH3OH(SO2(2H2O(2e(=SO(4H(24(NO2(e(H2O=NO(2H( 3(2)Al(Al(3e(4OH(=AlO(2H2O(0.3 2(3)(C(Ag ()(Fe3(e(=Fe2(解析(1)(电(化(电(电( C (化(2 (2 (H (化( 0 (1 ( CO (化( CO (电(电( CO(4e(4H(=CH3OH( A ( SO2(B ( O2(C ( H2SO4(化(电(电( SO2(2H2O(2e(=SO(4H( A ( NO2(B ( O2(C (24HNO3(化(电(电( NO2(e(H2O=NO(2H( 3(2)(化(电(化(2Al(2NaOH(2H2O=2NaAlO2(3H2( 2Al(6e(8OH(=2AlO(4H2O( 26H2O(6e(=6OH(3H2(2Al(3H2(5.4 g ( mol(0.3 5.4 327 2mol(3)(“Cu ( Fe2(SO4)3=2FeSO4(CuSO4”( Cu (化(电( Cu (Fe3(电(电( Fe2(SO4)3( Cu ( Cu(Fe2(SO4)3=2FeSO4(CuSO4(电( Cu(2e(=Cu2( 2Fe3(2e(=2Fe2(