1、 uC(0+)=U0，iL(0+)=0 uC(t),i(t),uL(t)RLC+iuCuL(t=0)+0dddd22 CCCutuRCtuLCtuCiCdd 2C2ddddtuLCtiLuL CLuRiu 则则:LCLRRp2/422,1 RLC+iuCuL(t=0)+012 RCpLCpLC2LRLR122 LCLRLRp1)2(222,1 tptpCeAeAu2121 ptCetAAu)(21 ()-tCu=Kesin t+CLR2 CLR2 2CLR 0)0()0(UuuCC 0)0(dd0 CitutC tptpCeeu2121AA RLC+iuCuL(t=0)+CLR2 021AAU
2、 0AA2211 pp0121201221AAUpppUppp )(2112120tptpCepepppUu )()()()(21211202121120tptptptpCeeppLUeppeppppCUdtduCi )()(2121120tptpLepepppUdtdiLu )(2112120tptpCepepppUu 1201ppUp 1202ppUp LCLRLRp1)2(222,1 0 dtdi 0212t1tppepep ln 2112pppptm)()(21120tptpeeppLUi)()(2121120tptpLepepppUdtdiLu 1221lnpppptm0)()(21
3、21120 tptpLepepppUu02121tptpepep 0212221tptpepepmtppppt2)ln(12221RLC+RLC+2,1 jp22022)2(-1 LRLC LCLRLRp1)2(222,1 2 LR CLR2)(212121tjtjttptpCeAeAeeAeAu )(tjtjtCeeeu 21AA01221AUppp01212AUpppsin)AA(cos)AA(2121tjtet sinBcosA ttet tjtetjtetjtj sincossincos)sin(costtUeutC 0 00BAUU )sincos(ttUet 0000 teULdt
4、duCitC sin 01 teUutCsin00teU 00teU 00 teUdtdiLutLsin00 teUutCsin00teULdtduCitC sin 01LCutUu)sin(200 t021 jp,2 10 ，LCtLUiC000 sintLUtuCiCC000dd sintUtUtiLuL00002dd cos)sin(tUtUuC00002 cos)sin(LRppp221)(tAAeutC21 0100UAUuC)(0201 UAUA)()(teUtiLuetLUtuCietUutLtCtC 1dddd 1 0 0 0 00dd210AAtutC)(CLR2 2 CLR tptpceAeAu2121 2 CLR)sin(tAeutc 2 CLR)tAA(eut c21 tUuC00 cos
