1、A A类（研究生）辅导课程类（研究生）辅导课程智力测试智力测试主讲老师：陈月娣B B类（英语专业）辅导课程类（英语专业）辅导课程智力测试智力测试主讲老师：陈月娣C C类（本科生）辅导课程类（本科生）辅导课程智力测试智力测试主讲老师：陈月娣D D类（专科生）辅导课程类（专科生）辅导课程智力测试智力测试主讲老师：陈月娣一、题型分析二、解题技巧及真题串讲三、复习指南一、题型分析一、题型分析(一)考核要求这类试题主要考查考生的逻辑推理、数字运算、常识判断及灵活应变的思维能力。由于试题以英文出现，所以同时也考查考生的英文水平。(二)试题结构5道小题，以问答或填空形式出题，其中部分试题配有图片。注意：客观
2、题主观题（2008年以前为multiple choice客观题型，从2008年开始试题基本上为填空形式的主观题，没有选项可供选择，客观题出题形式出现的频率很低）(三)试题特点1.区别于国内其他英语考试，是英语竞赛的特有题型，与国际英语考试GRE和GMAT中的数学题和逻辑题有相似之处；2.可归纳为数学题、空间逻辑题及语言文字题等三类；如：数学题One half of one quarter of one tenth of 800 is _.空间逻辑题Two diagonals have been drawn on two faces of the cube.Using logical reaso
3、ning and lateral thinking,work out the angle between the two diagonals AB and AC.语言文字题Only one other word can be made from all the letters of INSATIBLE.What is it?3.难度大，时间紧。做智力测试题有个特点，要么很快地得出答案，要么花费很长时间也不得要领，关键是解题思路是否正确。该部分分值不高（每题1分），比较合理的答题时间应该在5分钟左右，对大部分考生来说，时间比较紧张。这类试题也是很多英语学习爱好者很感兴趣的；做得好，能从中获得乐趣
4、。同时这部分题也是高水平学生拔高，拉出差距的地方。二、解题技巧及真题串讲二、解题技巧及真题串讲耐心研读试题，明确题目意思和题目所要考查的目标，找出题中隐含的规律，然后进行推导得出答案。(一一)数学题数学题首先是准确地理解题目要求，然后通过加、减、乘、除等运算找出数字之间的关系，最后对答案加以验证。数列 数字与图形结合 应用题 数列89 4 9 6 2 3 4 7 8 2 1 9 6 4 3 2Multiply by 7 the number of odd numbers which are immediately followed by an even number in the list a
5、bove.What is the answer?2010年D类决赛【答案】35【解析】紧跟在偶数后面的奇数有5个，分别是9、3、7、9、3。故5乘以7得35。odd number奇数。even number偶数。94 Jeff likes 25 but not 24;he likes 400 but not 300;he likes400 but not 145.Which of the following does he like?2012年D类初赛 A.10 B.50 C.124 D.200 E.1600【答案】E【解析】杰夫喜欢平方之后得出的数，25=52，400=202,144=122
6、，因此在选项中，他会选择1600，因为1600=402。）There were 12 runners in a marathon.They lined up as follows.2010年D类初赛What number should the 12th runner have?【答案】18.【解析】88=64 Reversed=4655=25 Reversed=5244=16 Reversed=6177=49 Reversed=9466=36 Reversed=6399=81 Reversed=18 Find the missing number.2008年C类初赛7 9 8 10 9?【答案
7、】11【解析】第一、三、五位置上的数依次为7、8、9；第二、四、六位置上的数依次为9、10、11。Find the next number in the sequence.2008年C类决赛1 2 5 12 27?【答案】58 【解析】这排数列之间的差依次是1，3，7，15。新数列之间的差又依次是2，4，8，可推测下一个数是16，往前推，上一个数列的下一个数是31，故题中所缺数字是58。91 Each number is the sum of the previous two numbers.What were the first two numbers that started the se
8、ries?2012年B类初赛【答案】2,5【解析】设19和81之间的数字为x,y，则19+x=y，x+y=81，得x=31，y=50。则后四个数分别为19，31，50，81。则前四个数从后往前可推知分别是12，7，5，2。What is the next number?2008年B类初赛 983,147,49,18,?.【答案】4 【解析】9832=147；1472=49；492=18；182=4 Which number comes next in this series?2008年B类决赛2736,9108,17127,89298,?,【答案】178596【解析】通过计算可知，2736+6
9、372=9108，9108+8019=17127，17127+72171=89298，即每个数字加上将每个数字倒过来读而得出的数字的和，即这个数字的后面一位的数。所以，89298后面的数应为89298+89298=178596。You are given a series of numbers.Your task is to see how they form a relationship with each other.You have to choose the number that would go next in the series.2007年A类决赛2 3 7 17 39 A.5
10、8.B.75.C.85.D.65.【答案】C 【解析】2+1=3，3+4=7，7+10=17，17+22=39，继而寻找1，4，10，22之间的规律。1+3=4，4+6=10，10+12=22，3，6，12之间是两倍递增关系，按规律，它们的下一个数值是122=24。22+24=46，39+46=85，故选项C为正确答案。86 Find the letter that goes inside the brackets to complete the sequence.2011年A类初赛108(O)648(S)325(T)214()【答案】I 【解析】通过题目可知，325-108=217，648-
11、214=434，故得出2(T-O)=S-?。在字母表中共有26个字母，我们把字母O、S、T分别对应第15位、19位、20位，代入2(T-O)=S-?，从而得出？=S-10，即字母？在字母表的顺序比S靠前10位，也就是字母I。数字与图形结合91 What number should replace the question mark?2009年D类初赛【答案】24 【解析】方框中的数字等于上下数字之差加左右数字之和。如28=24+6+（7-9）；27=9+8+（14-4），故9+10+（16-11）=2487 What number should replace the question mar
12、k?2011年D类初赛【答案】50【解析】找出第一行和第二行的数字规律，由此计算出第三行空格内的数字。第一行：58+26=84,84/2=42;第二行：39+45=84,84/2=42。可见第三行也应把两数相加的结果除以2。88 Clock A was correct at midnight,but lost exactly 1 minute an hour from then on.It stopped 1 hour ago(B),having run for less than l2 hours.What is the time now?2011年D类初赛【答案】6.00 am.【解析】从
13、A图到B图可知，时钟走了5个小时，但是一次差1分钟，共慢了5分钟，所以时钟所显示的4:55实际应为5点钟，因其是一个小时之前停的，所以现在应为6点钟。94 Each symbol is worth a number.The total of the symbols can be found alongside each row and column.What number should replace the question mark?2008年D类决赛【答案】22 【解析】由左边第一列可得出每个花的值是10；由第一行可得出三角形的值是8；由第二行可得出圆的值是3；由第二列可得出方框的值是1
14、。所有图形相加的和是22。87 Insert numbers into the grid,so that all calculations are correct both across and down.6 and 8 are already placed.2010年D类初赛【答案】【解析】涉及简单、较小的数字之间的加减乘除，可采用直接带数字法，将可能性数字带入以检验正确与否。If these two numbers total 6879,what do the two numbers below total?2011年C类初赛【答案】15189【解 析】将 纸 颠 倒 过 来，将 数 字
15、相 加。1261+5618=6879，6061+9128=15189。Correct this equation so that it makes sense by moving the four given digits but without introducing any additional mathematical symbols.2011年C类决赛【答案】72=49【解析】将2变成7的平方，将6翻转后移到4之后。What number replaces the question mark?2011年C类决赛【答案】6【解析】(167)(78)=2；(145)(25)=7以此类推，(
16、189)(93)=6 What number should replace the question mark?2010年C类决赛【答案】2.【解析】从最上部3开始，然后接第二排从右至左，然后接第三排从左至右，然后接第四排从右至左，即3 6 9 4 2 3 6 9 4 2 3 6 9 4？3，可得出规律36942一直被重复，故答案为2。What number should replace the question mark?2009年C类决赛【答案】2【解析】根据观察可知，4+8+9=2 1 0+1，3+4+5=110+2，所以，878=？10+3，从而得出？为2。49 Find the we
17、ight to balance the scales.2007年C类初赛 A.2kg.B.4kg.C.3kg.D.5kg【答案】A【解析】物理学杠杆平衡原理，两边力乘以力矩得出的积相加之和相等。4kg316kg1=10 kg2X4，X=2 kg。90 Find the missing value on the roof of the second house.Each of the numbers on the windows and doors must be used only once and no number can be reversed.2010年B类初赛【答案】71【解析】根据
18、第一个房屋712+4=88可推测左边窗户 门+右 窗=屋 顶，那 么 第 二 个 屋 顶 的 数 值 为88+7=71。What number is missing from the segment below?2010年B类决赛【答案】25 【解析】设圆的每一个分割部分中的三个数分别为a，b，c，按顺时针方向与之相邻的数设为d，如右图所示，四者之间的规律为ab=c+d，所以66=？11，即答案为25。Find the number that fits below the 7.2009年B类初赛【答案】11 【解析】数出图片中的数字一共有几条边。如果有N条边，则用N乘以三再减去原来的数，就得到
19、图片下方的数。如，图中1字共有11条边，则其下数字为113-1=32。图中4字一共有15条边，则其下数字为153-4=41。7字一共有6条边，所以7字下方的数字应为63-7=11。Which number is missing from the third circle?2007年B类初赛【答案】B 【解析】通过观察这三幅图，可以得出如下三个数学等式：87+57+36=180；49+23+18=90；36182。观察，等式可以得出，第1个图中数字之和是第2个图中数字之和的2倍。而第3个图中的27是第1个图中的36的34；第3个图中的和为l803/4=135。135-15-27=93。Plane
20、t“Y”orbits the Sun in six months.AB is four times the distance of CD and moreover it turns out that planet X travels at half the speed of planet Y.How long does Planet“X”take to orbit the Sun?2007年B类决赛 A.8 years.B.6 years.C.4 years.D.2 years.【答案】C 【解析】由题意可知AB=4CD，故X绕太阳一周的距离为Y的4倍，又planet X travels at
21、 half the speed of planet Y，故X绕太阳一周的时间为Y的8倍。Planet“Y”绕太阳一周的时间为6个月，故planet X绕太阳一周需4年。What is the missing number from the centre of the third target?2007年B类决赛 A.32.B.33.C.34.D.35.【答案】C 【解析】第一副图中间数字的得出可以看作是8216，第二副图中间数字的得出可以看作是13339，第三副图中间数字的得出可以看作是17234。Which number replaces the question mark?2011年A类初
22、赛【答案】29 【解析】顺时针看可以得出：24+21=45，21+17=38，17+5=22，5+24=29，故？=5+24，即29。What number is missing from the segment below?2008年A类决赛【答案】3【解析】图中的圆被分成8部分，其中共有4对图形相互对称，通过计算可知，对称的图形6个数字相加都等于30，故图中缺少的数字应为3045648，即3。应用题 A farmer has a field containing a certain number of pigs and hens.Between them they have 36 head
23、s and 100 feet.How many pigs and hens does the farmer have?2008年D类初赛【答案】14 pigs and 22 hens【解析】假设有x头猪，y只鸡，那么可得以下方程组：x+y=36，4x+2y=100；解此方程组可得x=14，y=22。89 An aircraft flew from A to B at an average speed of 230 mph.It returned from B to A at an average speed of 300 mph.What was its average speed for t
24、he two journeys?2010年D类初赛【答案】260 mpf【解析】设飞机从A到B耗时a小时，从B到A耗时b小时，那么可得出230a=300b；飞机飞行整个路程中所用的平均速度则为2300b/(a+b)；将两个方程式合并，便可得出平均速度约为260.3mpf，四舍五入后取结果260mpf。94 I bought four things this morning.The dictionary was 5 times the cost of the book，the tie was 30 times the cost of the book，the watch was 4 times
25、the cost of the tie，and I spent 312 dollars in total.What was the price of the dictionary?2008年D类初赛【答案】10 【解析】假设字典的价格为x，那么书的价格为1/5x,领带的价格为30*1/5x，手表为4*30*1/5x，这些东西的 总 价 值 为 3 1 2，因 此 可 得 方 程 式x+1/5x+30*1/5x+4*30*1/5x=312，故x=10。There is a four-digit number made with 1-9!Its 2nd digit is twice greater
26、 than its 3rd.The sum of all the digits is thrice greater than its last digit!The product of its 3rd and 4th digits is 12 times greater than the ratio of its 2nd to 3rd.What is it?2012年C类决赛【答案】7638【解析】这是一个四位数，第二个是第三个的两倍，有四种可能，2,1；4,2；6,3；8,4；然后设第四个数为a，第一个数为b，那么先假设第二第三位数为2,1，则a=12*2=249，不符合，同理4,2也不符合
27、，如果是6,3，则3a=12*2=24，a=8,，8+6+3+b=8*3=24，b=7，则这个四位数为7638，如果是8,4，则4a=12*2=24，a=6，6+8+4+b=6*3=18，b=01，不符合，所以，答案为7638。A census-taker calls at a house.He asks the woman living there the ages of her three daughters.The woman says,“If you multiply their ages the total is 72;if you add their ages the total
28、is the same as the number on my front door,which you can see.”The census-taker says,“That is not enough information for me to calculate their ages.”The woman says,“Well,my eldest daughter has a cat with a wooden leg.”The census-taker replies,“Ah!Now I can calculate their ages.”What are the ages of t
29、he three girls?2011年C类决赛【答案】8，3，3【解析】由于三个孩子年龄相乘得72，可以得出的组合有：7211,3621,1841,942,981,662,833,1261,1232,1822,643,24 3 1。各 组 合 相 加 之 后 得 到：74,39,23,15,18,14,14,19,17,22,13,28。人口普查员一定知道门牌号码，可是仍然无法确定是哪个组合，说明门牌号码是14，可知是662,833这两种情况中的一种，房主人又提到eldest daughter，说明，较大的两个孩子不可能同岁，故可以确定三个孩子的年龄分别是8岁，3岁，3岁。When Davi
30、d is twice as old as he is now he will be four times as old as his daughter Jane will be in five years time.If in 1990,four years ago,he was four times as old as his daughter,in what year was she born?2010年C类初赛【答案】In 1983【解析】由题目可知，四年前为1990年，则今年为1994年。可以设David的女儿今年为X岁，David为Y岁，根据题目条件可以列出一个两元一次方程组：4(X
31、+5)=2Y;4(X-4)=Y-4。解方程组可得：X=11，Y=32，即Jane今年11岁，又知今年为1994年，则1994-11=1983，即她出生于1983年。The cost of hiring a private rail carriage is shared equally by all the passengers who paid an exact number of pounds which was less than 100 each.The carriage has seats for 50 passengers and the total bill amounts to
32、1887.How many seats were not occupied?2010年C类初赛【答案】13seats(37 people each paid 51.)【解析】根据题目要求可知，1887英镑被一些人平分，人数少于50，每人所付钱数少于100英镑，可知如果分解1887的话，符合条件的两个因子应一个小于50，一 个 小 于 1 0 0。因 为 1 8 8 7=3 1 7 3 7，即1887=3629，或者1887=3751，可知是37位乘客，每位乘客交了51英镑，则空座为13个。87 A set of dominoes(多米诺)consists of rectangular(矩形的)
33、tiles each carrying two numbers from 0 to 6 which represented by patterns of spots.Every possible pairing of numbers occurs just once including each number with itself.How many dominoes are there in a set?2010年C类决赛【答案】28.【解析】该题是一个排列组合题，从0至6共7个数字任意选出两个数字，共有21种组合，除此之外，每个数字还可以跟自己组合，共有7种组合，加在一起共28种组合。89
34、 One hundred boys went on a school outing.Eighty-one percent of the boys lost a shoe,82 percent of the boys lost a sock,77 percent of the boys lost a handkerchief and 68 percent of the boys lost a hat.What is the minimum percentage who lost all 4 items?2010年C类决赛【答案】8%.【解析】81+82+77+68=308.若使丢4件物品的人数最
35、少，则丢3件物品的人数最大，即100人，由此可知丢4件物品的人数最少时应为8人，即丢4件物品的人数所占最小比例为8%。94 The following is part of a bus timetable.Express buses do not stop at some of the towns between Dawtry and Saresbury.2009年C类决赛DAWTRY 07:50 08:30 09:10 09:50TAMSVILLE 07:59 10:00BRISTOWN 08:07 08:42 10:08JAMCASTER 08:24 08:55 09:27 10:25SA
36、RESBURY 08:33 09:04 09:36 10:33 How much less time does it take to travel on the fastest express bus from Dawtry to Saresbury than it does on a slow(non-express)bus?【答案】17分钟【解析】根据题意，快车不会在一些小镇上停，故第二和第三辆车是快车，又因为第三辆车比第二辆车少停一个镇，故第三辆车是最快的快车，从Dawtry到Saresbury用了26分钟。第一辆车和第四辆车都用了43分钟。43减去26就是17。96 How many
37、different arrangements can you make of all the seven letters in the word COMBINE?2008年C类初赛【答案】5040 【解析】这是一个排列组合题目，计算方法为7*6*5*4*3*2*1=504096 How many minutes is it before 12 noon if 90 minutes ago it was four times as many minutes past 9 am?2008年C类决赛【答案】72 【解析】设是中午12点以前x分钟。根据题意可得此方程式：x=41260(90+x)960
38、解得x=7288 Simon had a bag of sweets.When he tried to divide the sweets into three piles he had one left over.The same thing happened when he tried to divide them into four,five and six piles.However,when he split them into seven piles there were none left over.How many sweets did he start with?2011年B
39、类初赛【答案】301【解析】求出3、4、5、6的最小公倍数，是60。列出不定方程60 x+1=7y。x=1、2、3依次带入。x=5时，y=43。5*60+1=301。87 If Alan gives Brenda$5.50,they will both have the same amount of money.If Brenda gives Alan 1.50,Alan will have twice as much as Brenda.What did they have at the start?2011年B类决赛【答案】Alan:$26.50 Brenda:$15.50【解析】假设Al
40、an最初有x美元，Brenda最初有y美元，可得方程组x-5.50=y+5.50,x+1.5=2(y-1.5)。方程可解，x=26.50,y=15.50Which park has twice as many llamas(美洲驼)as one of the parks has lions?2010年B类初赛【答案】Park C.【解析】题目问哪一个公园里的骆驼数是其中一个公园中狮子数的两倍，三个公园中狮子数分别为：16，14，10，二倍为：32，28，20，根据表中数据可知公园C中骆驼数为32，正好是公园A中狮子数的两倍，故答案为Park C。MonkeysLlamasLionsPark A
41、422516Park B352114Park C48321089 At the end of a banquet 10 people shake hands with each other.How many handshakes will there be in total?2010年B类决赛【答案】45 【解析】试想这十个人排成一排，那么站在最左边的人依次与右边九个握手，而左边数第二个至于其右边八 个 人 握 手 即 可，依 次 类 推，得 出 算 式：9+8+7+2+1=45。A farmer buys a horse for$60.He sells it to his neighbor
42、for$70.Then he discovers he could have made a better deal.He borrows$10 from his wife,and buys the horse back for$80.He then sells it to another neighbor for$90.How much money did he make?2008年A类决赛【答案】$10 【解析】第一次买马花费$60，卖了$70，共盈利$10。第二次买马花费$80，卖了$90，再除去借妻子的$10，共盈利$0。所以，通过两次对马的买和卖，他共盈利$10。There are 1
43、89 members in a tennis club:8 have been at the club less than three years;11 are under 20 years of age;70 wear spectacles;140 are men.What is the smallest number of players who have been members for three years or more,are at least 20 years of age,wear glasses and are men?2011年A类初赛【答案】2 【解析】分别算出多于3年
44、的为181人，不戴眼镜的为119人，女性为49人，且题目已知20岁以下为11人，则181-11-119-49=2。(二二)空间逻辑题空间逻辑题解答空间逻辑题的关键在于找出题目中的逻辑关联，一般从位置、方向、数量等角度入手。95 Which of the following diagrams is the odd one out?2012年D类初赛【答案】D【解析】D是唯一交叉部分的图形与原图不一样的，故选D。88 Connect the following 12 dots all using only five straight lines,which go through every dot
45、 only once.2010年D类初赛【答案】92 Each of the nine squares in the grid marked 1A to 3C,should incorporate all the lines and symbols which are shown in the squares of the same letter and number immediately above and to the left.For example,2B should incorporate all the lines and symbols that are in 2 and B.
46、One of the squares is incorrect.Which one is it?2009年D类初赛【答案】2A 【解析】此题为图像叠加得组合图形。2A应由2和A构成，2A错在缺少了A中的黑实心点。89 Two diagonals have been drawn on two faces of the cube.Using logical reasoning and lateral thinking,work out the angle between the two diagonals AB and AC.2011年C类初赛【答案】60【解析】连接BC，AB、BC、AC等长，等
47、边三角形内角为60。90 Which of the options given will fold up to make the cube below?2011年C类初赛【答案】A或C【解析】B、D项的十字面与圆圈面都是相对的。90 What is the largest number of regions this ring could be divided into using three straight lines?2010年C类初赛【答案】Nine regions【解析】前两条直线分别与小圆相切，使小圆充当区域的分界线，并且这两条线相交，第三条线穿过小圆，并与前两条直线相交，且不经过
48、之前的任何交点和切点。Look at the above group of three squares.They have a certain feature which is shared by only one of the groups of three squares below.Which one has the matching feature?2011年C类决赛 A.B.C.D.【答案】D【解析】原图三个矩形重叠的部分是一个三角形，只有D符合。90 Each of the nine squares in the grid marked A1 to C3 should incorp
49、orate all the lines and symbols which are shown in the squares of the same letter and number immediately above and to the left.One of the squares is incorrect.Which one is it?2010年C类决赛【答案】B1.【解析】图B1不正确。图B和图1两个图形合并后，图1没有保持原样。On the left are some shapes and the codes that go with them.You must decide
50、how the code letters go with the shapes.Which code should replace the question mark on the right?2009年C类初赛【答案】ZN 【解析】左边第一个图和第三个图相同的部分是两圆不重合的空白部分，相同的字母是M，所以M代表两圆不重合的空白部分，X代表两圆重合并且是阴影的部分，Z代表重合并且是黑影的部分，并且由这两个图可推导出第一个字母代表两圆中间的重和部分，第二个字母代表不重合的部分。所以右边的图有着与左边第三个图相同的字母Z和与左第二个图相同的字母N。95 There are five square
