1、tt6,6则解：令)sin21(2cos)2cos()232cos(2ttt31sin t97)232cos(0cossin3)cos()2cos(3解：31tan5691034tan1tan1cossin2sin21cos2sin21cos22222一12sin3)2cos1(1cossin32sin2)(2xxxxxxf解：)62sin(22cos2sin3xxx323mn根据图像：D答案为一xxxxxxf2sin22sin22sin2)22cos(12)22cos(1)(解：)22sin()(2sin)(axaxxg平移后函数解析式：)(2Zkka02sinaB答案为1)4sin(2)(
2、xxf解：单调递增在单调递减，在,0)4sin(,0)(axaxf43a24aC答案为一21)6sin(2cos1sin232cos2cos2sin3)(2xxxxxxxf解：kxkxf22622)(的单调递增时，D答案为Z),23,232()(kkkxf的单调增区间为：一33a解：)32sin(23)2cos1(32sin)(xxxxf 1,21()(xf)67,3(32),43,3(xx当xyxysin2sin2倍：伸长为原来的解：法一、将纵坐标)4sin(2sin24xyxy个单位：向右平移)421sin(2)4sin(22xyxy倍：的将横坐标伸长为原来xyxysin2sin2倍：伸长为原来的解：法二、将纵坐标)4sin(2)21sin(24xyxy个单位：向右平移)21sin(2sin22xyxy倍：的将横坐标伸长为原来一2)32(6解：A4个单位，选将点向左平移一)622sin()6)(2sin()62sin(xxyxy解：)622sin()62cos(xx又4,22一33A，得解：由最大值为2,)6(65wT又)2sin(3xyk232,0)32sin()0,3(代入，得：将3,2,23又k)32sin(3xy
